10x^2/7x-4=3

Solution for 10x^2/7x-4=3 equation:

10x^2/7x-4=3

We move all terms to the left:

10x^2/7x-4-(3)=0


Domain of the equation: 7x!=0

x!=0/7

x!=0

x∈R


We add all the numbers together, and all the variables

10x^2/7x-7=0

We multiply all the terms by the denominator


10x^2-7*7x=0

Wy multiply elements

10x^2-49x=0

a = 10; b = -49; c = 0;
Δ = b2-4ac
Δ = -492-4·10·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2401}=49$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-49}{2*10}=\frac{0}{20}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+49}{2*10}=\frac{98}{20}
=4+9/10
$